A spherical balloon of radius 60 cm subtends an angle of 60 degrees at a man's eye when the angle of elevation of it's centre is 45 degree. Find the height of the centre of the balloon.



Let BC be the height of centre of baloon, and height of top of baloon is BD.Here, CD= 60 cmBAD=60° and BAC=45°In right angled triangle BAC,tan45°=BCAB1=BCABAB=BCNow in triangle BAD,tan60°=BC+60AB3=BC+60BC3 BC=BC+603 -1BC=60BC=603-1=603+13-13+1=603+13-1=603+12=303+1=301.732+1=30×2.732=81.96 cm

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