A spherical hollow cavity is made in a lead sphere of radius R, such that its surface touches the outside surface of the lead sphere and passes through its centre. The mass of the sphere before hollowing was M. With what gravitational force will the hollowed-out lead sphere attract a small sphere of mass 'm', which lies at a distance d from the centre of the lead sphere on the straight line connecting the centres of the spheres and that of the hollow, if d = 2R:       

find the new center of mass of the lead balldensityD=M43πR3X=-43πR23DR2M-43πR23D=-43πR23M43πR3R2M-43πR23M43πR3=-MR16M-M8=-MR167M8=-R14distance of center of mass from the mass m r=2R+R14=29R14force on mass mF=G7M8m29R142Regards

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