A spring gets extended by a length of 1 mm when a force of 0 5 N is applied on - Physics - Oscillations

Question

A spring gets extended by a length of 1 mm when a force of 0 5 N is
applied on it What is the value of its spring constant? If the
springis extended by 0 25 m and released what will be its potential
energy a) when it is just released and b) when it is at an
extension of 0 1 m?

Rohit Babu · Accepted Answer

Dear Student,Given,F=0
5N, x=1mm=10-3mWe have,F=-kxMagnitude of spring constant is,k=Fx=0
510-3=500 N/m1)x=0
25mPotential energy is,U=12kx2=12×500×0
25×0 25=15 625J2)x=0 25-0 1=0 15mU=12kx2=12×500×0
15×0 15=5 625JRegards

A spring gets extended by a length of 1 mm when a force of 0.5 N is applied on it. What is the value of its spring constant? If the springis extended by 0.25 m and released what will be its potential energy a) when it is just released and b) when it is at an extension of 0.1 m?