A sprinter in a 100 m race covers 4m in first second, 30 m in next 4 seconds and 52 - Science - Motion

Question

A sprinter in a 100 m race covers 4m in first second, 30 m in next
4 seconds and 52 m in another 4 s and finishes the race in 10
seconds (1) Calculate the average speed of the sprinter? (2) What
is the peak value attained by the sprinter? (3) During which time
interval is the acceleration highest?(4) Plot the distance and
velocity time graph for the race? (5) Show on the graph the
velocity of sprinter at the end of 5 seconds?

Vijaya Nittala · Accepted Answer

Dear student,
1)Vag=total distance total time taken=100 m 1+4+4+10=5
263 m/s2) Peak speed = 50 meters in 5 second = 12
5 m/s4 m in 1 second= 4 m/s30 meters in 4 second = 30/4 =7
5 m/s50 m in 4 second = 12
516 m in 10 s = 1
6 m/s 3)acceleration first 1 s = 4-01=4 m/s2Acceleration 7
5-44-1=3 53=1 16  m/s2Acceleration 12 5-7 59-5=1
25 m/s2Acceleration1 6-12 519-9=-10 910=-1
09 m/s2Acceleration is maximum in  first second
Regards