A square shaped plane coil of area 100 cm2 of 200 turns carries a steady current of 5A. It is placed in a uniform magnetic field of 0.2 T acting perpendicular to the plane of the coil. Calculate the torque on the coil when its plane makes an angle of 60° with the direction of the field. In which orientation will the coil be in stable equilibrium ? 

Dear Student,
Please find below the solution to the asked query:
Torque acting on the coil:τ=BIAN cosθ =0.2×5×100×10-4×200×cos60o =1 N·mOrientation of stable equilibrium:Here, torque should be equal to zero.Plane of the coil is perpendicular to magnetic field, θ=90o 
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