A stone is dropped from the edge of roof

  1. how long does it take to fall 4.9 m?
  2. how fast does it move at the end of the fall?
  3. what is its accelration after one second and two second?

given that g:9.8m/s2

1)  s =ut +1/2at2

4.9 = 1/2(9.8)t2

t2 = 1 ; t =1

2) v = u + at

v = (9.8)1 = 9.8m/s

3) acceleraion is constant = 9.8m/s2

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a ) t = 1 s

b ) v = 9.8 m/s

c ) v =12.4 m/s

d )a = 9.8 m/ s2

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Ahisjanjsjjsjsj
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1)s=ut +1/2at2
4.9=1/2(9.8)t2
49/10=1/2(49/5)t2
1/2(49/5)t2=49/10
divide both sides of the equation by 1/2(49/5)
t2=1
t=1
2)Acceleration is constant=9.8m/2
3)v=u+at
   v=0+(9.8)1
    =9.8m/s
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Please questions this answer

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T=1 V=9.8 A=9.8
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