A stone is dropped from the top of a tower 200 m high in a pool of water at the base of the tower. When is the splash heard at the top?
(Given g = 10 m/s^2 and speed of the sound is 340 m/s)


Time taken to hear splash at top=(Time taken by stone to reach pool)+(time taken by this sound produced to be heard at top)

~~Time taken by stone to reach pool
 s=ut+1/2at2
 here s=200m u=0m/s(as when itwas dropped,it was at rest) a=g=10m/s2
On substituting values,
t=6.32s

~~time taken by this sound produced to be heard at top
s=d/t
here, s=340m/s d=200m
t=d/s=200/340=0.588s

Total Time=6.32+0.588=6.9s=Time taken to hear splash at top

 

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