A stone is dropped from top of the tower of height " h". After 1 second another stone is dropped from the balcony 20m below the top.

Both reach the bottom simultaneously. what is the value of h? taking g=10m/sec2

Given,Initial velocity, u=0 (In both the cases)Height of tower=hHeight of balcony=h-20When stone is dropped from the tower, suppose the time taken is t, then for the second case it will be t-1.Thus using equation of motion,h=ut+12gt2=0+12gt2----(i)and h-20=12g(t-1)2----(ii)Solving (i) and (ii), we gett=2.5 sand h=31.25 m

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