A stone is dropped from top of the tower of height " h" After 1 second another stone is - Physics - Motion In A Straight Line

Question

A stone is dropped from top of the tower of height "
h" After 1 second another stone is dropped from the
balcony 20m below the top
Both reach the bottom simultaneously what is the value of h?
taking g=10m/sec2

Jyoti Pant · Accepted Answer

Given,Initial velocity, u=0 (In both the cases)Height of tower=hHeight of balcony=h-20When stone is dropped from the tower, suppose the time taken is t, then for the second case it will be t-1
Thus using equation of motion,h=ut+12gt2=0+12gt2----(i)and h-20=12g(t-1)2----(ii)Solving (i) and (ii), we gett=2
5 sand h=31 25 m

A stone is dropped from top of the tower of height " h". After 1 second another stone is dropped from the balcony 20m below the top. Both reach the bottom simultaneously. what is the value of h? taking g=10m/sec2

A stone is dropped from top of the tower of height " h". After 1 second another stone is dropped from the balcony 20m below the top.

Both reach the bottom simultaneously. what is the value of h? taking g=10m/sec²