A stone is dropped into a well, 44.1 m deep. The sound of the splash is heard 3.13 s after the stone is dropped. Find the velocity os sound in air .

Time of hearing sound = 3.13 s

Time taken by the stone to reach the bottom of the well can be calculated by the relation :

s = ut + 1/2 at

^{2}

Since, u = 0 m/s and a = 9.8 ms

^{-2}

t

^{2}= 2s/a

we get, t = 3 sec

Since, the total time for the stone to reach the well and again to travel to same distance due to reflection of sound is 3.13 sec as the stone took 3 sec to reach the bottom of the well.

Therefore, the sound will only take to 0.13 sec to reach the observer who listened the sound.

Hence, speed of sound = $\frac{dis\mathrm{tan}cetravelledbythesound}{timetakenbythesoundtoreactheobserver}$

= $\frac{44.1m}{0.13s}=339.23m{s}^{-1}$

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