A stone is dropped into a well and its splash is heard at the mouth of the well after an interval of 1.45 s . find the depth of the well. given that the velocity of sound in air is equal to 332 m/s .
Assume depth of the well = d.
Using kinematics equation
s = ut + (1/2)at2 and u = 0, a = g, s = d
=> d = (1/2)gt2 ...........................(1)
velocity of sound in air = 332 m/s
Time in which sound travels = (1.45-t) s
d = speed sound * time
=> d = 332(1.45-t)......................(2)
Solve the equation (1) and (2) for d =........?