A stone is thrown vertically upward with a velocity 40m/s and is caught back. Taking g=10m/s2.calculate the maximum height reached by the stone

 Initial velocity(u) = 40m/s

Final velocity when stone reaches at max. height(v) = 0m/s

g( accln due to gravity)= 10m/s2

g is taken as -ve because it opposes the vertical motion

max. height of the stone reach (h) = ?

Using Equation

v2 = u2 +2as

v2 - u2 = 2gh

0- u2 = -2gh

h= u2 /2g

= (40)2 /2*10

h= 80 m

hence, max. height attained by the stone is 80 meters


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