A stone is thrown vertically upwards. It decelerates at a rate of 9.8m/s2. It reaches a greatest height of 16.53m. Calculate its initial speed.
Dear student
From the Newton's equation of motion.
v2-u2=2as
v=0 (final speed is zero)
a= -9.8
s=16.53
u=18 m/sec
Regards
From the Newton's equation of motion.
v2-u2=2as
v=0 (final speed is zero)
a= -9.8
s=16.53
u=18 m/sec
Regards