A stone is thrown vertically upwards. It decelerates at a rate of 9.8m/s2. It reaches a greatest height of 16.53m. Calculate its initial speed.

Dear student
From the Newton's equation of motion.
v2-u2=2as 
v=0 (final speed is zero)
a= -9.8 
s=16.53 
u=(2×9.8×16.53) 
u=18 m/sec

Regards

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