A stone of mass m is to be thrown to a height h a) With what minimum velocity should it be thrown? b)At what height does KE and PEbecome equal c)Find the velocity at that height. Share with your friends Share 0 Vara answered this (a)Kinetic energy at the ground=Potential energy at height h12mv2=mgh12v2=ghv=2gh(b)LetH=Height at which KE and PE are equalPE=mgHKE=mgh-mgHmgH=mgh-mgH3mgH=mghH=h3(c)velocity at height H:v'2-v2=2-gHv'=v2-2gH =2gh-2gH =2gh-H 0 View Full Answer Umang answered this 2gh= u^2 u = √2gh (ans 1 ) 0 Umang answered this at H/2 0