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A straight line plot showing the terminal potential energy (V) of a cell as a function of current ( I) drawn from it , is shown in the figure . Using this plot determine (i) the emf and (ii) internal resistance of the cell.

equation of graph is

$V=-\left(\frac{1.2-0.8}{0.12-0.04}\right)i+1.4\phantom{\rule{0ex}{0ex}}V=-5i+1.4$

emf is when current is zero

therefore emf is 1.4V

internal resistance is magnitude of slope hence 5ohm

regards

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