A string of lenght l and mass m is lying on the table on horizontal table.What is the tension in the string at a distance of x from the end of the force applied?

Dear Student,

Acceleration of rope,a=FmIf we consider ml be the mass per unit length, then mass for new length (l-x) is m'm'=m(l-x)lT=m'×aT=m'×FmT=m(l-x)l×FmT=F(l-x)l=F1-xl

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