A student recorded the mass of dry raisins as 5g and the mass of raisins after soaking in water as 48g. While performing the above experiment. The percentage of water absorbed by raisin is :

(a) 20% (b) 30% (c) 60% (d) 40%

Dear student,
Refer below for above asked query:-
Mass of dry raisins = w₁ = 5g

Mass of soaked raisins = w₂ = 48 g

Increase in mass=(48g - 5g) = 43 g

Percentage of water absorbed = (w₂ - w₁) X 100 / w₁

= (43 / 5) X 100

= 860%

The answer do not match with provided options , kindly check is there is any change in numericals in the question.

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