# A sum of rs.3000 is to be givenin form of 63 prizes. If the prize money is either rs.100 or rs. 25 . Find the number of prizes of each type?

Total sum = Rs 3000
Total number of prizes = 63
Let the number of prizes, each of Rs 100 be 'x’ and number of prizes, each of Rs 25 be 'y'
Then according to question
x + y = 63 (1)
100x + 25y = 3000 (2)

Equation (2) gives 4x + y = 120 (3)

Subtracting equation (1) form equation (3):

4x + yxy = 120 – 63
3x = 57
x = 19

Putting x = 19 into equation (1)
19 + y = 63
y = 63 – 19 = 44

Number of prizes, each of Rs 100 = 19
Number of prizes, each of Rs 25 = 44

Hope! This helps you.
Cheers!

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how we got 4x+y=120
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4+3+45 = 52
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prizes of rs.100=19
prizes of rs.25=44
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45 degrees
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P =10
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A total of rs 80000 is to be distributed amount 200percent as prize.prize is either rs500 or rs100 find each prize
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?

Total sum = Rs 3000

Total number of prizes = 63

Let the number of prizes, each of Rs 100 be 'x? and number of prizes, each of Rs 25 be 'y'

Then according to question

x?+?y?= 63?(1)

100x?+ 25y?= 3000?(2)

?

Equation (2) gives 4x?+?y?= 120?(3)

?

Subtracting equation (1) form equation (3):

?

4x?+?y???x???y?= 120 ? 63

3x?= 57

x?= 19

?

Putting?x?= 19 into equation (1)

19 +?y?= 63

y?= 63 ? 19 = 44

?

Number of prizes, each of Rs 100 = 19

Number of prizes, each of Rs 25 = 44

?
• -1
ans : total sum = Rs 3000
Total number of prizes = 63
Let the number of prizes, each of Rs 100 be 'x’ and number of prizes, each of Rs 25 be 'y'
Then according to question
x + y = 63 (1)
100x + 25y = 3000 (2)

Equation (2) gives 4x + y = 120 (3)

Subtracting equation (1) form equation (3):

4x + y – x – y = 120 – 63
3x = 57
x = 19

Putting x = 19 into equation (1)
19 + y = 63
y = 63 – 19 = 44
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