A tent is in the form of a cylinder of diameter 4 2 m and height 4 m, surmounted by - Maths - Surface Areas and Volumes

Question

A tent is in the form of a cylinder of diameter 4 2 m and height 4
m, surmounted by a cone of
equal base and height 2 8 m Find the capacity of the tent and the
cost of canvas for making the
tent at Rs 100 per sq m

Varun.Rawat · Accepted Answer

We have,diameter of base of cylinder, d = 4
2 mNow, radius of base of cylinder , r= 2
1 mHeight of cylinder, h = 4 mNow, volume of cylinder = πr2h = 227×2
1×2 1×4 = 55
44 m3Now, radius of base of cone, r = 2
1 mheight of cone, h1 = 2
8 mNow slant height of cone, l = r2+h12 = 4
41 +7 84  = 12 25 = 3
5 mNow, volume of cone = 13πr2h1 = 13×227×2
1×2 1×2 8 = 12
936 m3So, capacity of tent = volume of cylinder + volume of cone = 55
44 + 12 936 = 68
376 m2Now, CSA of cylinder = 2πrh = 2×227×2
1×4 = 52
8 m2Now, CSA of cone = πrl = 227×2
1×2 8 = 18
48 m2Area of canvas used = 52
8 + 18 48 = 71
28 m2Cost of 1 m2 of canvas = Rs 100Cost of 71
28 m2 of canvas = Rs 100 × 71
28 = Rs 7128

A tent is in the form of a cylinder of diameter 4.2 m and height 4 m, surmounted by a cone ofequal base and height 2.8 m. Find the capacity of the tent and the cost of canvas for making thetent at Rs.100 per sq. m.

A tent is in the form of a cylinder of diameter 4.2 m and height 4 m, surmounted by a cone of
equal base and height 2.8 m. Find the capacity of the tent and the cost of canvas for making the
tent at Rs.100 per sq. m.