A TRADER BROUGHT A NUMBER OF ARTICLES FOR Rs 900 , FIVE ARTICLES WERE FOUND DAMAGED HE SOLD EACH - Maths - Quadratic Equations

Question

A TRADER BROUGHT A NUMBER OF ARTICLES FOR Rs 900 ,
FIVE ARTICLES WERE FOUND DAMAGED HE SOLD EACH OF THE REMAINING
ARTICLES AT Rs 2 MORE THAN WHAT HE PAID FOR IT HE GOT A PROFIT OF
Rs 80 ON WHOLE TRANSACTION FIND THE NUMBER OF ARTICLES HE BOUGHT
Reply soon PLEASE!

Gursheen kaur. · Accepted Answer

Let the total number of articles bought by the trader = x.

Cost price of x article = Rs 900

∴Cost price of 1 article $= Rs. \frac{900}{x}$

As 5 articles were damaged, then the number of articles sold by the trader = (x –5).

Selling price of (x-5) articles=900+80=Rs.980

Selling price of each articles = $(\frac{980}{x - 5})$

Given:

$(\frac{980}{x - 5}) - (\frac{900}{x}) = 2 \Rightarrow [\frac{980 x - 900 (x - 5)}{x (x - 5)}] = 2 \Rightarrow [\frac{980 x - 900 x + 4500}{x (x - 5)}] = 2 \Rightarrow 980 x - 900 x + 4500 = 2 x (x - 5) \Rightarrow 80 x + 4500 = 2 x^{2} - 10 x o r 2 x^{2} - 10 x - 80 x - 4500 = 0 \Rightarrow 2 x^{2} - 90 x - 4500 = 0 \Rightarrow x^{2} - 45 x - 2250 = 0 \Rightarrow x^{2} - 75 x + 30 x - 2250 = 0 \Rightarrow x (x - 75) + 30 (x - 75) = 0 E i t h e r (x - 75) = 0 o r (x + 30) = 0 \Rightarrow x = 75 o r \Rightarrow x = - 30 N e g l e c t - v e t e r m$

The total number of articles bought by the trader = 75

A TRADER BROUGHT A NUMBER OF ARTICLES FOR Rs 900 , FIVE ARTICLES WERE FOUND DAMAGED. HE SOLD EACH OF THE REMAINING ARTICLES AT Rs 2 MORE THAN WHAT HE PAID FOR IT. HE GOT A PROFIT OF Rs 80 ON WHOLE TRANSACTION . FIND THE NUMBER OF ARTICLES HE BOUGHT. Reply soon PLEASE!