A train is moving with a uniform velocity of (2i-j+4k)m/s. If the force required to overcome the friction is (i-3j+2k)N, what is the power of the engine? Share with your friends Share 6 Sanat K Mukherjee answered this Dear student, Power of the engine = F.→v→ = (i-3j+2k).(2i-j+4k) = 2+3+8 = 13W Regards, 11 View Full Answer