A tree is broken by the wind but does not seperate. If the point from where it breaks is 9m above the ground and its top touches the ground at at a distance of 12m from it's foot,find out the total height of the tree before it broke.

In right ΔABC, using Pythagoreas theorem, we get

Thus, total height of the tree before it broke  = 9m + 15m

  = 24 m

  • 1

Total height of the tree = 12m sq + 9m sq

                                         =  144 + 81

                                         = 225

                                         = 15m  

  • 4

 let one side be perpendicular=12m

another side be base=9m

therfore H2=rootunderp2+b2

=root under92+122

=root under81+144

=root under 225

=15

total height =h+p

=15+12

=27m ans

  • -2
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