A truck is moving with a velocity if 72km/h and it takes 3s to stop after the brakes are applied.calculate the force exerted by brakes.mass of truck is 1200kg.

m = 1200 kg

u =0

v = 72kms/hr = 20 m/s

t = 3 secs

v = ut + at

20 = 0 + ax3

a = 20/3 =6.66

 

F = ma

F = 1200 x 6.66

F = 7992 N

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use the formula f= m*(v-u) divided by t

f= 1200*(0- 72)/3

f=28800N

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