# A TV tower has a height of 100m. How much population is covered by the TV broadcast if the average population density around the tower is 1000 persons per sq km?

We know $d=\sqrt{2Rh}$
Where R is the radius of earth , and h is the height of the tower.
Therefore Area over the earth surface where TV Broadcast reaches= ${\mathrm{\pi d}}^{2}=\mathrm{\pi }\left(2\mathrm{Rh}\right)$
Thus the population is covered by the TV broadcast =(density)(Area)= $1000×\mathrm{\pi }×2\mathrm{Rh}.=1000×3.14×2×6378×0.1=4005384$

• -2

d =2rh1/2

calculate d by this meathod, then1000 persons = 1 km2

then in d2 population= 1000 x d2

• 9

First calculate coverage range (d) by using (2RH)1/2 where R is radius of earth and H is the ht. given ------- (1)

Then, Area (A) = (3.14)d2 From (1)

Finally , Total population = Area * 1000

• 15
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