​A uniform chain of length l and mass m overhangs a horizontal table with its 3/4 part on the table. the friction coefficient between the table and
​​the chain is ?.find the work done by the friction during the period the chain slips off the table?friction coeff =0.2 g=10m/s L=2m and m=16kg

Dear student, 

Consider an element of chain as shown in figure, 

WD by friction force, when this element covers a distance is, 
dW=dF.s=-μdmg×x (direction of F and displacement is opposite)W=03l4-μgxdmW=03l4-μgxMldxW=-μg3l422×Ml=-932μMglPutting all given values, we get, W=-18 J

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