A VERTICAL CYLINDER CLOSED AT BOTH ENDS IS DIVIDED INTO TWO PARTS INTO TWO FRICTIONLESS PISTON EACH PART CONTAINING ONE MOLE OF AIR.AT TEMPERATURE 300K, THE VOLUME OF UPPER PART IS 4TIMES THAN THAT OF THE LOWER PART. AT WHAT TEMPERATURE WILL THE VOLUME OF THE UPPER PART BE THREE TIMES THAN THAT OF THE LOWER PART?

Dear Student,

P2=Pt+P1PV=nRTor, P=nRTVor, nRTV2=nRTV1+Ppr, P=nRT(1V2-1V1)and, V=V1+V2When V1=aV2                 V=V2(a+1)or, V2=Va+1SImilalry, V2=1a+1V1or, V=1a+1V1+V1or, V=V1+1aor, nRT(1+aV-1+1aV) =Pn=1RT1V(a-1a)=Por, RT1V(a1-1a1)= P  and RT2V(a2-1a2)= PLet total pressure, P be 1 thenT2T1×(a2-1a2)(a1-1a1)=1T2300×(3-13)(4-14)=1T2300×(83)(154)=1T2300×83×415=1or, T2=4532×300=421.87 K

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