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A vertical pole which is 2.25 m long casts a 6.75 m long shadow on the ground. At the same time , a vertical tower casts a 90 m long shadow on the ground .Find the height of the tower.

The height of the tower is 30m.

  • -3
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70 m

  • -6

 Height of the pole=2.25m

shadow=6.75m

shadow of a vertical tower=90m

thus,

height of the vertical tower=90*2.25/6.75

 =30m

  • 6

6.75/2.25=3 from here we get =the shadow is three times so 90/3=30 hence solved

  • -4

70 cm is wrong answer

  • -5

consider a triangle ABE andtriangle CDE

B=D=90

E=E

ABC =CDE (AA)

THEREFORE AB DIVIDE BY CD =BE DIVIDE BY DE (CPST)

AB*6.75 =90*2.25

AB=30

  • 1
Please send the figure..it would be a great help Exam tomorrow:(
  • -1
😎 #azzdoomer Follow me on Instagram: @azzdoomer

  • 4
The higher of the tower is 30m

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Given,

 

Length of the vertical pole = 6 m

 

Shadow of the pole = 4 m

 

Let the height of the tower be h m.

 

Length of the shadow of the tower = 28 m

 

Class 10 Maths Chapter 6 Triangles 04

 

In ΔABC and ΔDFE,

 

∠C = ∠E (angle of elevation)

 

∠B = ∠F = 90°

 

By AA similarity criterion,

 

ΔABC ~ ΔDFE

 

We know that the corresponding sides of two similar triangles are proportional.

 

AB/DF = BC/EF

 

6/h = 4/28

 

h = (6 ×28)/4

 

h = 6 × 7

 

h = 42

 

Hence, the height of the tower = 42 m

Regards
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