A vessel containing gas at a pressure of 60 cm of hg was connected to arm A of open end - Chemistry - States of Matter

Question

A vessel containing gas at a pressure of 60 cm of hg was connected
to arm A of open end manometer The atmospheric pressure was
recorded as 74 cm of hg If the mercury in arm A stand at 84 5 cm
height,the mercury in arm B will stand at (a) 70 5 cm (b) 74 cm
(c)24 5 cm (d) 88 cm

Ashwini Kumar Mishra · Accepted Answer

Dear student ,

Let the mercury stands at a level of p cm then the difference of
the two arms = p - 84 5
Now , pressure of the gas = atmospheric pressure + difference of
mercury levels
60 = 74 + (p - 84 5 )
Then p = 70 5 cm
option (a) is correct
Regards

A vessel containing gas at a pressure of 60 cm of hg was connected to arm A of open end manometer.The atmospheric pressure was recorded as 74 cm of hg.If the mercury in arm A stand at 84.5 cm height,the mercury in arm B will stand at (a) 70.5 cm (b) 74 cm (c)24.5 cm (d) 88 cm