A vessel of cylindrical shape without a lid is made from a sheet of metal.Find the area of metal required, if the length of a vessel is 48 cm and its diameter is 28 cm.  

 2 X pi X r X h + pi X r2

= 2 x 22/7 x 14 x 48 + 22/7 x 142

= 88 x 48 + 22 x 28 = 22(192 + 28) = 22 x 220 = 4840 sq.cm

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1344  SQ.CM
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This question is i textbook solutions 
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Total Surface Area of a cylinder = 2*pi*r(r+h)
TSA for the cylinder above = ​pi*r(r+h)
=> 22/7 * 14 (48+14)
=> 44*62 = 2728 cm2
Therefore, the metal required to make the cylinder is 2728 cm2.
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2728cm2
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2728cm2
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2728cm2
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2728 CM2
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formula = pie*r*h(h+r)- pie*r
             =22/7*14*48(14+48)-22/7*14
              =22*2*48*62-22*2
              =44*48*62-44
             =  25664408cm​2
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2728cm2
 
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answer is 4840cm.sq
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Total surface area of cylinder =2?rh(r+h) ...... Then add all the given dimension and ur answer will be 2728cm
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Total Surface Area of a cylinder = 2*pi*r(r+h)
TSA for the cylinder above =??pi*r(r+h)
=> 22/7 * 14 (48+14)
=> 44*62 = 2728 cm2
Therefore, the metal required to make the cylinder is 2728 cm2.
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Please find this answer

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2728cm​2
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2728cm^2 is the ans
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2728
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2727cm
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2728     cm2
 
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2728cm^2
 
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4840cm^2
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1344 sq  m
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2728cm2
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Total Surface Area of a cylinder = 2*pi*r(r+h)
TSA for the cylinder above =??pi*r(r+h)
=> 22/7 * 14 (48+14)
=> 44*62 = 2728 cm2
Therefore, the metal required to make the cylinder is 2728 cm2.
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2728 cm^2 is the answer
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2728
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Total Surface Area of a cylinder = 2*pi*r(r+h)
TSA for the cylinder above =??pi*r(r+h)
=> 22/7 * 14 (48+14)
=> 44*62 = 2728 cm2
Therefore, the metal required to make the cylinder is 2728 cm2.
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2728cm square
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2728
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Please find this answer

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2728cm
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I hope this will help.

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2728cm2
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Total metal required=csa +area of one circle

=22/7×2×48×14+22/7×14×14

=4224+616

=4840cm2
 

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1344cm square
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Total Surface Area of a cylinder = 2*pi*r(r+h)
TSA for the cylinder above =??pi*r(r+h)
=> 22/7 * 14 (48+14)
=> 44*62 = 2728 cm2
Therefore, the metal required to make the cylinder is 2728 cm2.
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