A weightless rod of length 2 l carries two equal masses m, one secured at lower end A and the - Physics -

Question

A weightless rod of length 2 l carries two equal masses m, one
secured at lower end A and the other at the middle of the rod B The
road can rotate in vertical plan about a fixed horizontal axis
passing through C What horizontal velocity must be imparted to the
mass at A so that it just completes the vertical circle

Sandeep Kumar · Accepted Answer

Dear Student

From the law of conservation of energy
Potential energy=Kinetic enrgyP=Kmgl+mg(2l)=mvB22+mvA22The road rotate at some angular velocity, when it become verticalω=vBl+vA2lvA=2vBThus3mgl=mvB22+m(2vB)22vB=6gl5

Regards