A wire having a linear density 0.1kg/m is kept under a tension of 490 N. It is observed that it resonates at a frequency of 400Hz. The next higher frequency is 450 Hz. Find the length of the wire

Dear student
Formula of velocity on the string isv=Tμ=4900.1=4900=70m/sLet length of the wire be l.Let the wire vibrate forming n loops when it resonates with 400Hz.so l=nλ12...1v=f×λ170=400×λ1λ1=70400 l=nλ12=n2×70400=n2×740...2Let the wire vibrate forming (n+1 )loops when it resonates with 450Hz. l=(n+1)λ22...1v=f×λ270=450×λ2λ1=70450 l=(n+1)λ22=n2×70450=(n+1)2×745...3from eqn 2 and 3n2×740=(n+1)2×745n8=n+199n=8n+8n=8from eqn 3l=(8+1)2×745=92×745=710=0.7m=70cmRegards

  • 52
What are you looking for?