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A wire having length 2.0 metres diameter 1.0 mm and resistivity 1.963 into 10 to the power minus 8 ohmmeter is connected in series with a battery of EMF 3 volt and and internal resistance one ohm calculate the resistance of the wire current in the circuit

5.98 ohm
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  • -8
2.98
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R=0.625×10^-5ohm and I=4.8×10^5Ampere
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A wire of having
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R is 5×10^-2 . Current is 60 ampere 
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Solution with steps plz for 34th question

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R= 0.05 ohm I= 2.85A

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