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A wire is in a shape of a rectangle. its lenght is 40 cm and breadth is 22cm. if the same wire is rebent in the shape of a square then what will be the measure of each side.

Perimeter of rectangle = Perimeter of square

2 (Length + Breadth) = 4 × Side

2 (40 + 22) = 4 × Side

2 × 62 = 4 × Side

Side == 31 cm

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length of the rectangle = 40cm

breadth of the rectangle = 22cm

area of the rectangle = (40*22)cm

=880cm2

if the wire is bent in the form of a square then the square's area will also be 880cm2

area of a square = side * side

=29.67*29.67

=880

therefore the side of the square is 29.67

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Answer:

Length of the rectangle = 40 cm.

Breadth of the rectangle = 22 cm.

So the area of the rectangle = Length x Breadth = 40 x 22 = 880 cm2.

Since the same wire is bend to make a square, then the area of the sqaure will be equal to the area of the rectangle.

Area of a square = Side x Side = Side2.

Side2 = 880

Side =√880 = 29.66 cm.

Ans: 29.66 cm.

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