A wire of length 'l' and resistance 'R' is twisted to make its thickness 2 times. What is the new resistance of the wire ? ANS - R/16 ohm EXPLAIN Share with your friends Share 13 Neha Gupta answered this let A is the area of the wire and l is the length of the wired is the initial thickness of the wireand d' is the final thickness of thewired' = 2dl' = new length of the wiresince volume of the wire remains samev1=v2πd22l =πd'22l 'l' = l4resisatnce of the wire is given by:R1= ρlA= ρlπd22R2R1 = ρl'πd'22ρlπd22 =ρl/4π2d22ρlπd22 =116R2 = R16 26 View Full Answer Ujjwal answered this An electric lamp is marked 100W, 200V. It is used for 5 hour daily. Calculate (i) its resistance while glowing (ii) energy consumed in kWh per day. 14 Anti Matter answered this The volume remains the same of the wire soif the length is doubled the area will be reduced to half so that the volume remains the same because you are changing only the length or the area but not the volume -4
