a wire of resistance 20 ohm is bent to form a closed square. what is the resistance across the diagonal of the square ?

Please refer to the answer posted by your friend above, it is correct.

@Alina...Good job, keep it up!

  • -15

1/Resistance=1/R1 + 1/R2

Therefore ,1/R=1/10 + 1/10


thus R=10/2=5

Therefore the ans is 5 Ohms.

  • 24

Since the wire is bend in the form of a square and we know that the sides of square are equal so each side will have same resistance i.e. 5 ohms.Now if we make a diagonal so the two faces in each side of a diagonal will have two sides and the resistance will be 10 ohms

So the total effective resistance will be

1 / R = 2 / 10 = 1 / 5

R = 5 ohms

Hope it helpz :)))

  • 50
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