a wire of resistance 20 ohm is bent to form a closed square. what is the resistance across the diagonal of the square ?
Since the wire is bend in the form of a square and we know that the sides of square are equal so each side will have same resistance i.e. 5 ohms.Now if we make a diagonal so the two faces in each side of a diagonal will have two sides and the resistance will be 10 ohms
So the total effective resistance will be
1 / R = 2 / 10 = 1 / 5
R = 5 ohms
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