a wire whose resistance is 80 ohm is cut into 3 pieces of equal lengths which r then arranged in - Physics - Current Electricity

Question

a wire whose resistance is 80 ohm is cut into 3 pieces of equal
lengths which r then arranged in parallel calculate d resistance of
d combination,

Kranav Sharma · Accepted Answer

As answered
previously

The
resistance of 80 ohm is cut into three
pieces
We know,
resistance, R = ÏL/A
Ï is
resistivity, L is the length, A is the area of cross-section of the
wire When it is cut into three equal pieces, Ï and A remains
constant but L changes
Since,
resistance is directly proportional to length So, if the length
becomes L/3 the resistance also becomes R/3 Thus, the resistance of
each piece is 80/3 ohm Now, we have three such pieces connected in
parallel The equivalent resistance of the combination
is,
1/R eq = 1/(80/3)
+ 1/(80/3) + 1/(80/3)
=>
1/R eq =
9/80
=>
R eq = 80/9 = 8
88 ohm

a wire whose resistance is 80 ohm is cut into 3 pieces of equal lengths which r then arranged in parallel.calculate d resistance of d combination,.