a wooden box of mass 8 kg slides down an inclined plane of inclination 30 to the horizontal wi5h a constant acceleration of 0.4m/s .what is the force of friction between the box and inclined plane?
F=ma
mgsin30° - Fric = ma
8×10×1/2 - Fric = 8×0.4
40 - Fric = 3.2
40 - 3.2 = Fric
Friction = 36.8