AB and DC are two vertical poles placed opposite to each other at a distance of 36 m from each other such that the points B and D are at ground level. If the length of AB is 30 m and the length of CD is 15 m, find AC. (Hint: Draw CE ⊥ AB and join AC.)
in triangle AEC
angle E=90 degrees
AE=15m
EC=36m
AC= as per pithgoras theorum
15^2+36^2=AC^
225+1296=1521
=39^2
AC^2 =39^2
AC=39 "^" is power of the no.
angle E=90 degrees
AE=15m
EC=36m
AC= as per pithgoras theorum
15^2+36^2=AC^
225+1296=1521
=39^2
AC^2 =39^2
AC=39 "^" is power of the no.