AB and DC are two vertical poles placed opposite to each other at a distance of 36 m from each other such that the points B and D are at ground level. If the length of AB is 30 m and the length of CD is 15 m, find AC. (Hint: Draw CE ⊥ AB and join AC.)

in triangle AEC
angle E=90 degrees
AE=15m
EC=36m
​AC= as per pithgoras theorum 
15^2+36^2=AC^
225+1296=1521
               =39^2
AC^2 =39^2
AC=39                                                             "^" is power of the no.
 
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