AB || CD || EF and GH || KM. If HGB =75 and KHD = 40 Show that HKM = 145 Share with your friends Share 1 Manbar Singh answered this We have,AB ∥ CD ∥ EF and GH ∥ KM.Produce GH to L and KM to N.Since CD ∥ AB and HG is a transversal.∴ ∠ HGB + ∠ GHD = 180° Sum of consecutive interior angles on sameside of transversal is 180°⇒ 75° + ∠ GHD = 180°⇒ ∠ GHD = 105°Since GL ∥ MN and HK is a transversal,So, ∠ HKM = ∠ GHK Alternate Interior Angles⇒ ∠ HKM = ∠ GHD + ∠ KHD⇒ ∠ HKM = 105° + 40°⇒ ∠ HKM = 145° 1 View Full Answer