AB is a chord of the circle x2 + y2 = 9 . The tangents at A and B intersect at C . If M (1,2) is the mid-point of AB than the area of triangle ABC is = ? Share with your friends Share 1 Rahul Raj answered this dear student the diagram will be circle centre is (0,0) and radius =3OM=(1-0)2+(2-0)2=5OA=radius=3AM=OA2-OM2=9-5=2length of chord AB=2*2=4tanθ=AMOM=25further angle CAB=angle BAO (angles in alternate segment)tanθ=CMAM=25CM2=25CM=45area of triangle ABC=12×AB×CM=12×4×45=85 regards 6 View Full Answer