AB is a line segment of fixed length 6 units joining the points A(t,0) and B which lies on positive y axis. P is a point on AB distant 2 units from A. find locus of P as t varies ​

Hello Supreetha, let B be (0,k)
As AB = 6 and PB = 2 it implies that P divides AB in the ratio 4:2 i.e 2:1
So with A(t,0) and B(0,k) the point of trisection P being nearer to A is
(2t/3 , k/3)
But t^2 + k^2 = 6^2
So k = ​​​​​​​​​​​​​​​​./(36-t2)
Hence P {(2t/3) , ​./(36-t2)/3}
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This is what I've tried

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Hope it helps👍....... :-)

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This is how we get the locus..I hope. this helps

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What are you looking for?