ABC is a right triangle with the size of angle ACB equal to 74 degrees. The lengths of the sides AM, MQ and QP are all equal. Find the measure of angle QPB. Share with your friends Share 6 Shruti Tyagi answered this Dear student, In rt ∆ABC,∠A+∠B+∠C=180°∠A=180°-74°-90=16°also, In ∆AMQ, As AM=MQ⇒∠AQM=∠MAQ =16°--(equal sides have equal ∠s opp. to them)∠AQM+∠MAQ +∠AMQ=180°∠AMQ=180°-16-16=148°also, ∠AMQ+∠QMP=180° (linear pair)∠QMP=180°-148°=32°In ∆QMP, QM=QP ⇒ ∠QMP=∠QPM=32°--(equal sides have equal ∠s opp. to them)∠QPM+∠QPB=180°--(linear pair)∠QPB=180°-32°=148° Regards 1 View Full Answer Pratyaksh Mahajan answered this IN TRIANGLE ABC, BY ANGLE SUM PROPERTY 90+74+x=180 180-164=ANGLE QAM ANGLE QAM=16 BUT AM=QM SO, QAM=AQM IN TRIANGLE AMQ, BY ANGLE SUM PROPERTY 16+16+ANGLE AMQ=180 ANGLE AMQ=180-32 =148 BY LINEAR PAIR AMQ +QMP=180 148+QMP=180 QMP=32 BUT QM=QP SO, QMP=QPM BY LINEAR PAIR QPM+QPB=180 QPB=180-32 QPB=148 3