ABC is an isoscels triangle in which A is (-1,0),ANgle A= 2pie/3,AB=AC and AB is along the x axis. If BC=4root3, then find the equation of the line BC.

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Please find below the solution to the asked query:

We haveA-1,0A=2π3AB=ACBC=43Let mid point of BCbe AD

As AB=AC, henceB=CAlsoA+B+C=π2π3+B+C=πB+B=π3B=π6=CBC=43BD=23cosB=BDABcosπ6=23AB32=23ABAB=4As A is -1,0 and B also on x-axis and AB=4, henceCo-ordinates of B=-1+4,0=3,0Also slope of line BC=π-π6=5π6Hence equation of BCis y-0=mx-3y-0=tan5π6x-3y=-13x-3

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