abcd is a parallelogram and e is the midpoint of bc the side dc is extended such that it meets - Maths - Understanding Quadrilaterals

Question

abcd is a parallelogram and e is the midpoint of bc the side dc is
extended such that it meets ae when extended at f prove that df =
2dc 
 dear sir/mam i want this answer fast plsssssss!!!!!!!!!!!!!!!
fastttttttttttt!!!!!! plzzzzz!!!!!!!!!

Ashutosh Verma · Accepted Answer

Answer :

We have ABCD is a parallelogram , So AB = CD , AB | | CD and BC =
DA , BC | | AD

And

CE = BE = BC2 = AD2 , As given " E " is mid point of line
BC

In triangle ADF AD | | CE , So from conserve of mid point theorem ,
we get

CFCE=  DFAD⇒CFDF=  CEAD⇒CFDF=  AD2AD⇒CFDF=  AD2AD⇒CFDF=  12⇒DF=  2 CF⇒CF=  DF2  , So " C " if mid point of line DF , SO ⇒DC = CF=  DF2⇒DC=  DF2⇒DF=  2 DC                                                            ( Hence proved )

abcd is a parallelogram and e is the midpoint of bc the side dc is extended such that it meets ae when extended at f. prove that df = 2dc. dear sir/mam i want this answer fast plsssssss!!!!!!!!!!!!!!! fastttttttttttt!!!!!! plzzzzz!!!!!!!!!