ABCD is a parallelogram in which BC is produced to E such that CE =BC. AE intersects CD at F . Show that area OF TRIANGLE BDF = 1/3 of area(ABCD).

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The reason given in fourth step is wrong. The correct statement is:

If a triangle and a parallelogram are on the same base and between the same parallels, the area of the triangle is equal to half of the parallelogram.

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