ABCD is a parallelogram, P is a point on AB such that AP : PB = 3 : 2 - Maths - Triangles

Question

ABCD is a parallelogram, P is a point on AB such that AP : PB = 3 :
2 Q is a point on CD such that
CQ : QD = 7 : 3 If PQ meets AC at R, then AR : AC is​
(A) 5 : 11 (B) 6 : 13 (C) 4 : 7 (D) 2 : 5

Atharva Kumar · Answer

Its option b hope this help you@@@@
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ABCD is a parallelogram, P is a point on AB such that AP : PB = 3 : 2. Q is a point on CD such that CQ : QD = 7 : 3. If PQ meets AC at R, then AR : AC is​ (A) 5 : 11 (B) 6 : 13 (C) 4 : 7 (D) 2 : 5

ABCD is a parallelogram, P is a point on AB such that AP : PB = 3 : 2. Q is a point on CD such that
CQ : QD = 7 : 3. If PQ meets AC at R, then AR : AC is
(A) 5 : 11 (B) 6 : 13 (C) 4 : 7 (D) 2 : 5