ABCD IS a square of length 5m. Charges 50C, - 50C, 50C are placed at sides A, C and D. Find net electric field at B. Share with your friends Share 11 Ravi Gupta answered this field due to charge at A, is directing away form the point A.EA = k×5052EB = k×5052 along the charge at B.So there net field is E = EA2+EB2 = 2×k×5052in the direction of 45 degree with AB.Field due to charge at C.Ec = k×5050 along the direction ACSp net field is given by:E' = E2+Ec2 = 2+14××k×5052 = 9×109×5025×32 = 27×109 v/m along AB -21 View Full Answer