ABCD is a square of side lenght 1 unit. A circle is tangent to two sides of ABCD and passes through exactly one of verices. the radius of circle is

a) [2+ 21/2] b) 2- 21/2 c) 0.5 d) 3/2

ABCD is a square of each side of length 1 unit.Let the circle has two tangents CD and BCwhich touches the circle at E and Frespectively.OE is radii and it is perpendicular to the tangent.OC = 12AC   diagonals of a square bisect each otherAC = 12+12 =2   (by pythagoras theorem in ABC)So, OC =22 In ODC, By Pythagoras theorem,OE  = OC2-CD2 = 24-14 =12 = 0.5

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