ABCD IS QUADRILATERAL WITH AB =X AD = b & AC =2a+3b. if area is X times the area of parallrlogramwith AB ,AD AS ADJACENT SIDES THEN X IS

We have :AB = a; AD = b; AC = 2a + 3bNow, area of quadrilateral ABCD = area of ABC +  area of ACD=12AB × AC + 12AC ×AD=12a×2a + 3b + 122a + 3b×b=122a×a + 3a×b + 122a×b + 3b×b=120 + 3a×b + 122a×b + 0=123a×b + 2a×b=52a×b=52AB×AD=52area of gm ABCDSo, x = 52

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