ABCDEF is a regular hexagon,,, Prove that AB + AC + AD + AE + AF = 6AO.

(direction sign {--} is present on the top of AB , AC,AD,AE,AF and 6AO)

Question

ABCDEF is a regular hexagon,,, Prove that AB + AC + AD + AE + AF
= 6AO
(direction sign {--} is present on the top of AB , AC,AD,AE,AF
and 6AO)

Ajanta Trivedi · Accepted Answer

<img alt="" src=
"https://s3mn%20mnimgs%20com/img/shared/content_ck_images/images/pic10%20png"
style="width: 172px; height: 154px;">
given: ABCDEF is a regular hexagon with center O
AB+AC+AD+AE+AF=AB+AC+AF+AD+AE=AB+AC+CD+AD+AE [since AF=CD]=AB+AD+AD+AE=2AD+AB+AE=2AD+ED+AE  [since AB=ED=2AD+AD=3AD=3*2AO   [since O is the center and AO=OD=6AO

hope this helps you

ABCDEF is a regular hexagon,,, Prove that AB + AC + AD + AE + AF = 6AO. (direction sign {--} is present on the top of AB , AC,AD,AE,AF and 6AO)

ABCDEF is a regular hexagon,,, Prove that AB + AC + AD + AE + AF = 6AO.

(direction sign {--} is present on the top of AB , AC,AD,AE,AF and 6AO)