A b o d y i s t h r o w n f r o m t h e s u r f a c e o f t h e e a r t h w i t h v e l o c i t y g R e 2 a t s o m e a n g l e w i t h t h e v e r t i c a l . I f t h e m a x i m u m h e i g h t r e a c h e d b y t h e b o d y i s R e 4 , t h e n c h o o s e t h e c o r r e c t o p t i o n ( s ) . ( R e = R a d i u s o f e a r t h ) ( A ) t h e a n g l e o f p r o j e c t i o n f r o m t h e v e r t i c a l i s sin - 1 5 4 ( B ) t h e v e l o c i t y o f t h e b o d y a t t h e m a x i m u m h e i g h t i s v = g R e 10 ( C ) t h e a n g l e o f p r o j e c t i o n f r o m t h e v e r t i c a l i s sin - 1 5 6 ( D ) t h e v e l o c i t y o f t h e b o d y a t t h e m a x i m u m h e i g h t i s z e r o Share with your friends Share 0 Vipra Mishra answered this Dear Student Let the angle of projection is α with horizontalH=u2sin2α2gRe4=gRe/2sin2α2gsin2α=1α=90So angle with vertical θ =90-90=0 degreeVelcoity of body at maximum height is always zero. So correct option is D Regards 0 View Full Answer
